Village
Sanborn
O'Brien County • Iowa • United States
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Also known as sanbon · sanbwrn · sang bo en · snbwrn aywwa · synbwrn ayywwa · Санборн
Sanborn is a village in O'Brien County, Iowa, United States. It has a population of about 1,392, an area of 4.9 km², and an elevation of 473 m. It is on Central Time. It lies 11 km north of Primghar. Its nearest neighbours are Primghar (11 km), Hartley (14 km), and Sheldon (16 km). 3 official videos are published about the United States.
- Time zone
- America/Chicago
- Coordinates
- 43.1816, -95.6556
- Population
- 1,385
- Area
- 4.9 km²
- Elevation
- 473 m
- Official website
- sanborniowa.com/index.php
Nearby places
Referenced in
Nou ka jwenn enfòmasyon sou kote sa a, e nou ka jwenn yon sèvis ki byen òganize e ki pa gen okenn rapò ak pwodui ki fèt.
Place data from GeoNames, used under CC BY 4.0 and modified for this site.


